Part 2 (2/2)

_10. Cib._ 8. Lamat. 6. Ahau. 4. Eb. 2. Kan.

_10. Ahau._ 8. Eb. 6. Kan. 4. Cib. 2. Lamat.

13. _Kan._ _11. Cib._ 9. Lamat. 7. Ahau. 5. Eb.

13. _Lamat._ _11. Ahau._ 9. Eb. 7. Kan. 5. Cib.

13. _Eb._ _11. Kan._ 9. Cib. 7. Lamat. 5. Ahau.

13. _Cib._ _11. Lamat._ 9. Ahau. 7. Eb. 5. Kan.

13. _Ahau._ _11. Eb._ 9. Kan. 7. Cib. 5. Lamat.

3. Kan. 1. _Cib._ _12. Lamat._ 3. Lamat. 1. _Ahau._ _12. Eb._ 3. Eb. 1. _Kan._ _12. Cib._ 3. Cib. 1. _Lamat._ _12. Ahau._ 3. Ahau. 1. _Eb._ _12. Kan._

An inspection of this table shows us that the five days repeated in each column are the same as those on the right of the quadrilateral of our scheme (Fig. 2), and are exactly in the order obtained by arranging the days of the month in four columns in the manner heretofore shown. (See column 4, Table IV.)

If I am correct in my supposition, we then have one clue to, if not a full explanation of, the method of obtaining the day columns in the Ma.n.u.script Troano.

[Ill.u.s.tration: FIG. 3.--Copy from Plates 18 and 19, Codex Peresia.n.u.s.]

Not this only, for this table of the Codex Peresia.n.u.s furnishes us also the explanation of the red numerals found over the day columns in the Ma.n.u.script Troano. Take, for example, Plate XIX, first or upper division, given also in my Study of The Ma.n.u.script Troano, p. 176, here the number is IV, corresponding with column 4 of the above table (V), where the days are the same and the numeral prefixed to each day is 4.

Plate XXVI (Study Ma.n.u.script Troano, p. 177), lower division, the days are the same and the number over the column is XIII, corresponding with the sixth column of Table V. This corroborates the opinion I expressed in my former work, that the number over the column was to be applied to each day of the column.

Why is the order of the numerals in the extract from the Codex Peresia.n.u.s precisely the same as the numbering of the Ahaues? I answer, because each column, if taken as referring to the four cla.s.ses of years, will, when the number of the month is given, determine just the years of an Ahau; or a fancy of the artist to follow an order considered sacred.

To ill.u.s.trate, let us take the next to the right-hand column of the table where the numeral is 1, and let us a.s.sume the month to be Pop, or the 1st. Then we have 1 Cib, 1 Ahau, 1 Kan, 1 Lamat, and 1 Eb of the first month, and from this data we are to find the years. As there can be four years found to each of these days, that is a Cauac year with 1 Cib in the first month, a Muluc year with one Cib in the first month, a Kan year with one Cib in the first month, an Ix year with one Cib in the first month, a Kan year with one Ahau in the first month, &c., it is evident that there will be, as the total result, just twenty years.

As I cannot repeat here, without occupying too much s.p.a.ce, the method of finding the years, I must refer the reader to Study Ma.n.u.script Troano, p. 23, _et al._ Hunting them out, by using our Table III, we find them to be as follows:

1 _Cib._ 1 _Ahau._ 1. _Kan._ 1. _Lamat._ 1 _Eb._[TN-8]

Years 10 Cauac. 13 Cauac. 9 Cauac. 5 Cauac. 1 Cauac.

Years 2 Kan. 11 Kan. 1 Kan. 10 Kan. 6 Kan.

Years 7 Muluc. 3 Muluc. 12 Muluc. 8 Muluc. 11 Muluc.

Years 12 Ix. 8 Ix. 4 Ix. 13 Ix. 9 Ix.

If we turn now to Table XVII (Study Ma.n.u.script Troano p. 44), we will find that these are precisely the counted years (those in the s.p.a.ce inclosed by the dotted lines) in Ahau number VI.

If we a.s.sume the month to be the 11th then the numbers of the Ahaues will correspond exactly with the numbers of the columns of our Table V.[8]

As it may be supposed that using the same numeral to any five days of the twenty in this way will produce a similar result, let us test it by an example. For this purpose we select the same column of our foregoing table, No. V--that with the number 1 prefixed--Cib, Ahau, Kan, Lamat, Eb, but in place of Lamat we insert Cimi. Hunting out the years as heretofore we find them to be as follows:

1 _Cib._ 1 _Ahau._ 1 _Kan._ 1 _Cimi._ 1 _Eb._ Years 10 Cauac. 13 Cauac. 9 Cauac. 7 Cauac. 1 Cauac.

Years 2 Kan[TN-9] 11 Kan. 1 Kan. 12 Kan. 6 Kan.

Years 7 Muluc. 3 Muluc. 12 Muluc. 10 Muluc. 11 Muluc.

Years 12 Ix. 8 Ix. 4 Ix. 2 Ix. 9 Ix.

If we try to locate these years in an Ahau in Table XVII (Study Ma.n.u.script Troano p. 44), we shall find it impossible to do so, nor can we locate them in any table that can be made which has either twenty-four or twenty years in an Ahau, while on the other hand the twenty years obtained by using a column of the table from the Codex Peresia.n.u.s can be located in some one of the Ahaues obtained by any division of the Grand Cycle into consecutive groups of twenty-four years that can be made. It would require too much s.p.a.ce to prove this a.s.sertion, but any one who doubts its correctness can test it.

As the extract we have given from the Codex Peresia.n.u.s relates only to one of the four groups of days--that on the right of the quadrilateral--I will supply in the following tables, Nos. VII, VIII, and IX, the arrangement of the groups of the other three sides; adding the other (Table VI), also, so as to bring the four together in the order of the sides of the quadrilateral, commencing with the line on the right, next the upper one, and so on.

While this is undoubtedly the order in which they are to be taken; which is the proper one to commence with? is a question yet to be discussed.

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